Answer:
1.84ft
Step-by-step explanation:
From the figure attached,
AB = Height of the window = 15ft
Let the distance between the base of the housr and the fence 'C' = xft
If the angle of depression = 7°
Then angle of elevation of the top of the fence from the house = 7°
Now from right triangle ABC,
tan7° = x/15
x = tan7°×15
x = 0.1227×15
x = 1.84ft
Therefore, distance of the house from the fence is 1.84ft
Answer:
•Lower confidence limit = $155.2109
•Upper confidence limit ,= $174.5891
Step-by-step explanation:
We are given:
U = 17
x' = $165.40
S.d = $21.70
a = 10℅ (90℅ confidence interval)
For s.d(x'), we have:
S/√u =
= 5.2630
Therefore, S.E (x') = $5.2630
At a= 0.10 (90℅ confidence level)
and degree of freedom = 16 (17-1)
90℅ confidence interval all around sample mean, will be:
(x' ± ; a S.E (x')
= (165.4±(174.6)(5.2630)
(165.5±9.189)
($156.2109, $175.5891)