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lorasvet [3.4K]
3 years ago
12

What are some fractions equivalent to -1/4

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0

Answer:

-2/8, -4/16, -8/24

Step-by-step explanation:

Elden [556K]3 years ago
6 0

Answer:

-2/8

-4/16

-8/32

-16/64

-25/100

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Multiply. (w-7) (w+4)
olganol [36]
(w - 7)(w + 4)

w^2 - 7w + 4w - 28

w^2 - 3w - 28
3 0
3 years ago
Read 2 more answers
Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t
Yanka [14]

Answer:

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

\hat p=\frac{X}{n} estimated proportion of  scissors selected for each friend

p_o=\frac{1}{3}=0.333 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:  

Null hypothesis:p\geq 0.333  

Alternative hypothesis:p < 0.333  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

6 0
4 years ago
Imagine that 30% of all U.S. Households own a dog, P(A)=.3 and that 10% of U.S. households own a Honda vehicle, P(B)=.1. In addi
Ksivusya [100]
P(A|B)= P(B and A) / P(A)

P(B and A) = .3 + .10 = .13 P(A)= .3

So,
P(A|B)= .13/.3

P(A|B)= 0.43333...
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3 years ago
14n+6p-8n=18p solve for n
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N=2p. Blah blah not part of the answer
4 0
3 years ago
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I have no idea how to simplify this, please help
yuradex [85]
3yx-1
i think (the -1 is an exponent)
3 0
3 years ago
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