Question

Imagine that 30% of all U.S. Households own a dog, P(A)=.3 and that 10% of U.S. households own a Honda vehicle, P(B)=.1. In addition, you know that 60% of dog owners own a Honda, P(A|B)=.6. What is the probability of a household owning a Honda given that they are a dog owner?

Answer 1

P(A|B)= P(B and A) / P(A)

P(B and A) = .3 + .10 = .13 P(A)= .3

So,
P(A|B)= .13/.3

P(A|B)= 0.43333...