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3 years ago

Can someone give me the points??

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

i want points too =)

Step-by-step explanation:

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zzz [600]

Answer:

Step-by-step explanation:

The only value for b that makes the equation true is 0.

8 0

3 years ago

A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates w

Allushta [10]

Answer: Option 'B' is correct.

Step-by-step explanation:

Number of pounds of candy = 30

Cost per pound = $1.10

Total amount would be

$30\times 1.10\\\\=33$

Let the number of pound that sold at $1.50 per pound be 'x'.

Let the number of pound that sold at 90 cents per pound be '30-x.

According to question, we get that

$1.5x+0.90(30-x)=33\\\\1.5x+27-0.90x=33\\\\1.5x-0.9x=33-27\\\\0.6x=6\\\\x=\dfrac{6}{0.6}=10$

Hence, there are 10 pounds of chocolates worth $1.50 per pound.

Therefore, Option 'B' is correct.

8 0

3 years ago

Wyatt surveyed 200 of the students in his school about their favorite color. 30% said their favorite color was purple. How many

zalisa [80]

60. 200 x .3 equals 60

8 0

3 years ago

Read 2 more answers

Suppose that Professor Rodgers needs one small group of students from his class to participate in a focus group. There are 11 st

irinina [24]

Answer:

(A) 165

(B) 330

Step-by-step explanation:

Total number of students in the class = 11

(A) How many different combinations of 3 selected students can he create?

ⁿCₓ = n! ÷ [(n - x)! x!]

n = 11, x = 3

11! / [8! 3!] = 165

HINT: 8! or 8 factorial represents [8x7x6x5x4x3x2x1]

(B) How many different combinations of 4 selected students can he create?

ⁿCₓ = n! ÷ [(n - x)! x!]

n = 11, x = 4

11! / [7! 4!] = 330

Same hint applies here, for all numbers with the factorial sign.

4 0

3 years ago

What is the answer and how do you solve 21x^3/3x^−1

Sunny_sXe [5.5K]

Answer:

as written: 7x^2

perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b/a^c = a^(b-c)

6 0

3 years ago