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enot [183]
3 years ago
12

If you need more Spad

Mathematics
1 answer:
aksik [14]3 years ago
6 0

Answer:

Just convert the number to the third digit and the answer will be b

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What is the value of 11g - 9k + 3 when g = 9 and k = 11?<br> Neatly show your work.
fenix001 [56]

Answer:

3

Step-by-step explanation:

11g - 9k + 3

Let g = 9 and k =11

11 * 9 - 9*11 +3

Multiply

99 - 99 +3

Add

3

4 0
2 years ago
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9th out of 10 questions
Mazyrski [523]

Hello! When dividing fractions, you multiply by the reciprocal of the second fraction. So 2/3 divided by 1/2 would be 2/3 times 2.

As you can see, the first fraction would be the same. Therefore, a will be 4. 5 and 6 will swap, so b will be 6 and c will be 5.

Therefore, our answer is D) a=4, b=6, c=5

I hope this helps!

8 0
3 years ago
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How and what is the answer
lana [24]
C ) 131 is the answer

in the upside-vertex (not inverted) triangle, angle to your left hand side would be equal to x (as interior alternate angles) = 68

and the angle to the right would be 180-y= 180-117 = 163 (as linear angles)

so the angle at the vertex = 180 - (68 + 163) =49  (as angles in a triangle sum upto 180)

so the angle mz = 180 - 49 = 131 degrees (as linear pair of angles or angle in a straight line)
4 0
3 years ago
Jane has 15 coins in total of $2.18. She has 5 more quarters than nickels, has 3 pennies and dimes. How many quarters, nickels,
fredd [130]
She has 7 quarters two nickels and 3 dimes
8 0
3 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
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