Width of the rectangle is 5 units
<u>Explanation:</u>
Let length (l) = l units
Given,
width (b) = l-3 units
Area of rectangle = 40 units
We know,
Area of rectangle = l X b
If l = 8 units then, b = 8-3 units
b = 5 units
Therefore, width of the rectangle is 5 units.
Answer:
Photo.
Step-by-step explanation:
A: The graph of the system is all points in the graph that suit 4x-2<y</=-5/2x-2
B: The point (-2,-2) is not included in the solution area. While it suits the second equation, it doesn't suit the first, ruling it out as a possible solution. If you plug in -2 as both y and x in the equation 4x-2>y, you'll get -8>-2, which is false. So, it is not a solution.
Answer:
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Step-by-step explanation:
You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of which gives you
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