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Eduardwww [97]
3 years ago
10

Kelly has a pool in her backyard, and she wants to build a fence around the entire area. Kelly's backyard is 14 meters wide and

15 meters long. It costs $6.63 per meter to install a wooden fence. How much would it cost to put a wooden fence around Kelly's backyard?
Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer:

perimeter of backyard=2(15+14)=58m

it cost

1m=$6.63

58m=$6.63×58=$384.54

therefore it cost

$384.54 to put a wooden fence around Kelly's backyard.

bulgar [2K]3 years ago
6 0

Answer:

  • $384.54

Step-by-step explanation:

Dimensions of the backyard is 14 m by 15 m

<u>The length of the fence is the perimeter of the backyard.</u>

  • P = 2(l +w)
  • P = 2(15 + 14) = 2(29) = 58 m

One meter of the fence costs $6.63

<u>Cost of the entire fence is:</u>

  • 58*$6.63 = $384.54

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Answer: x=-6

Step-by-step explanation:

Given

2x + 8 = -4

Subtract 8 on both sides

2x + 8 - 8 = -4 - 8

2x = -12

Divide 2 on both sides

2x / 2 = -12 / 2

x = -6

NOTE: I assume the questions "solve for c" actually means "solve for x"

Hope this helps!! :)

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2 years ago
This year jake is 47 in tall. This is 4 more than he was last year. Write and solve an equation to find out how tall jake was la
Solnce55 [7]

Answer:

x + 4 = 47

x = 43

Step-by-step explanation:

i minus 4 from 47 to get x by its self and x = 43 do he was 43 inches last year

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3 years ago
Find the value of x that will make A||B 4x 3x+10 x=
Ede4ka [16]

Answer:

4x 3x+10 x= 10

Step-by-step explanation:

3 0
3 years ago
A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three s
makvit [3.9K]

Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = Length \times Breadth = xy

We are given that the area of the garden is 122 square feet

So, xy=122 ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

Total cost = 30x+20y

Substitute the value of y from A

Total cost = 30x+20(\frac{122}{x})

Total cost = \frac{2440}{x}+30x

Now take the derivative to minimize the cost

f(x)=\frac{2440}{x}+30x

f'(x)=-\frac{2440}{x^2}+30

Equate it equal to 0

0=-\frac{2440}{x^2}+30

\frac{2440}{x^2}=30

\sqrt{\frac{2440}{30}}=x

9.018 =x

Now check whether it is minimum or not

take second derivative

f'(x)=-\frac{2440}{x^2}+30

f''(x)=-(-2)\frac{2440}{x^3}

Substitute the value of x

f''(x)=-(-2)\frac{2440}{(9.018)^3}

f''(x)=6.6540

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

(9.018)y=122

y=\frac{122}{9.018}

y=13.528

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

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Felt

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3 years ago
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