To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
Step-by-step explanation:
Answer:
<h2>
x = −7 and x = 33</h2>
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
You have to have exactly the same thing underneath the radical. So for example in choice A you have sqrt(2) and sqrt(3) underneath the radical. They are not the same. Choice A is not the answer.
Choice B has the same problem sqrt(5) is not the same thing as sqrt(3) and choice B is not the answer.
Choice C has sqrt(5) and sqrt(6) as your choice. They are not the same. C is not correct.
D is the answer. Both choices have sqrt(7) as the radicals. They are both 7. They are the same.
Answer:
2
Step-by-step explanation:
See the photo for the steps. :)
