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timama [110]
3 years ago
6

Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0.

Mathematics
2 answers:
Scilla [17]3 years ago
8 0

Answer:

a= 16

b= 2

Step-by-step explanation:

edge 2021

RUDIKE [14]3 years ago
7 0

Answer:

SS

Step-by-step explanation:

SS

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Use CALCULUS to find coordinates of the turning point on C.
antiseptic1488 [7]
Oi 

Just calculating the differential. Step by step:

y=12 \sqrt{x} -x \frac{3}{2}-10 \\  \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \  \sqrt{x} =x^{ \frac{1}{2} }}  \\  \\  Differentiating \\  \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\  \\  y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\  \\  y'=6. \frac{1}{x^{ \frac{1}{2} }}  -1. \frac{3}{2}  \\  \\  \boxed{y'=\frac{6}{ \sqrt{x} }  -\frac{3}{2}}

If you want to know where the tangent has no slope:

\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\  \\  \frac{6}{ \sqrt{x} } = \frac{3}{2}  \\  \\ 3 \sqrt{x} =12 \\  \\  \sqrt{x} = \frac{12}{3}  \\  \\  \sqrt{x} =4 \\  \\   (\sqrt{x})^2 =4^2 \\  \\ x=16
3 0
3 years ago
Light travels about 180 million kilometers in 10 minutes. How far does it travel in one minute? How far does it travel in one se
astraxan [27]

Answer:

18 million kilometers in one min. and 0.3 million kilometers in one second

Step-by-step explanation:

so the one min. is easy because all you have to do is take 180 and divide it by 10 and you get 18 million kilometers in one min. and then you would take 18 and divide it by 60 and you would get 0.3 million kilometers in one second

8 0
3 years ago
Read 2 more answers
A certain company makes three grades (A, B, and C) of a particular electrical component. Historically, grade A components have a
IrinaK [193]

Answer:

following are the solution to this question:

Step-by-step explanation:

In part (a):

Phase 1: Identifies a reasonable confidence period with both the title or form and checks suitable conditions. one z-interval test, p, that true percentage of defective parts in such a lot of Clauses:

1. Unique component sampling

2. This survey size is enough, to the fact to conclude the composition of that percentage of a sample was roughly natural, which the amount for successes and the number of losses are either greater than 10 (or 5 or 15). Needs to check: A 200-component representative selection of a big batch was picked. Each has far more than 15 achievements or failures (16 and 184).

Phase 2: Mechanisms Correct Pick problems for Pink and Blue it Committee of a College. Similar products are part of the program of a College Board. It is prohibited for such resources to be used and distributed online or in a printed form far beyond the participation of the college in the package, which leads to intervals (0.0424, 0.1176).

Phase 3: Background analysis In just this study, we consider 95% of its computed value to have between 4.24% and 11.76% for both the real number of defective components within the batch.

In part (b):

Its standard deviation of 95 percent found in Part (a) allows a company to eliminate class A as its 2 percent faulty rate is not among the computed value within this interval. It period however does not enable the company to decide between levels B and C, since the two faulty rates (5% and 10%) were examined.

Scoring: In 4 components the question is rated. Section 1 comprises part (a) step 1; part (a) or step 2 comprises of the part (a), part (3), part (a), and part (4) (b). The part was marked as correct (E), partly right (P) (I).

4 0
3 years ago
A model airplane is shot up from a platform 1 foot above the ground with an initial upward velocity of 56 feet per second. The h
Law Incorporation [45]
H=-16t^2+56t+1, the airplane is shot up from a platform 1 foot above the ground, so 1= - 16t^2+56t+1, we solve this equation
(- 16t+56)t=0, (- 16t+56)=0 or t=o, - 16t+56=0, implies t =3.5s
so the answer is C)3.5 seconds 
4 0
3 years ago
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School A and B are competing in an academic contest. at the beginning of the final round, school A has 174 points and school B h
7nadin3 [17]

X = number of correct answers

Y = number of incorrect answers

School A has 174 points and school B has 102 points.

A = 174

B = 102

School A has the same number of correct and incorrect answers during the final round.

A = 174 + 10X - 6Y

School B gives no incorrect answers and the same number of correct answers as school A.

B = 102 + 10X

The contest ends with the two schools tied.

Score = 174 + 10X - 6Y = 102 + 10X

174 + 10X - 6Y = 102 + 10X

5 0
3 years ago
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