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noname [10]
3 years ago
7

Write an equation of the line with the given properties. Your answer should be written in standard form.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Given:

The slope of the line is m=0.

The line passes through the point P(-9,-3).

To find:

The equation of the line in standard form.

Solution:

Standard form of a line is:

Ax+By=C

The slope intercept form of the line is

y-y_1=m(x-x_1)

Where, m is the slope and (x_1,y_1) is the point on the line.

It is given that the slope of the line is 3 and it passes through the point (-9,-3), so the equation of the line is

y-(-3)=0(x-(-9))

y+3=0

y=-3

Therefore, the standard form of the given line is y=-3.

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How do you do this the test is tomorrow and I forgot how to do this?
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Some things you need to know:

1) You need to know how to convert standard form to slope y-int. form and slope y-int. form to standard form.

2) When two lines are parallel, the slopes are the same.

3) When two lines are perpendicular, the slopes are negative reciprocals of each other. (Or their product is -1)
    example: 3/4 --> -4/3.
                    3/4 * -4/3 = -12/12 = -1

4) To find the value of b, substitute the point into the equation.

5) Convert the equation to slope y-int. form to find the slope.

6) When a line has an undefined slope, the slope y-int. will look either like
    y = __ (forms horizontal line) or x = __ (forms vertical line).
    To find the perpendicular of these lines, turn y to x / x to y.
    To find the value of __, look at the point located in the line, so if x = ___
    passes through (5,3), then x = 5 because x = 5 in the point. So the
    equation would be x = 5.

Use online practice tests and other sources if you don't understand.
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