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slamgirl [31]
2 years ago
14

I have an easy and quick question. So the picture shows an answered question but how do you know to divide? I just don't underst

and.....

Mathematics
2 answers:
11111nata11111 [884]2 years ago
8 0

Answer:

Ok so u know to divide bc u r trying to isolate the variable and that means undoing the function in this case 0.6 is multiplied to p so u do the opposite which is division

tada

Hope this helps :)

Pls give brainliest XD :)

aleksandrvk [35]2 years ago
5 0

Answer: You're looking for what P represents

Step-by-step explanation:

You start off with the equation

then subtract the number without the variable in this case both sides. Leaving 4.5-4.5= 0 and 22.5-4.5= 18

You also need to have p as P=n  (n= the number)

The equation 18/.6- 30, however you are looking for

0.6 divided by 18 which equal 0.33

so p=0.33

You might be interested in
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
3 years ago
If you help me with this fast I will brain you.<br> Thanks.
irakobra [83]

Answer:

-2 and -6 is the correct answer

5 0
3 years ago
1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+10 times 2
Maksim231197 [3]

Answer:

200

Step-by-step explanation:

<u>Step 1:  Add</u>

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

21 + 7 = 28

28 + 8 = 36

36 + 9 = 45

45 + 1 = 46

46 + 2 = 48

48 + 3 = 51

51 + 4 = 55

55 + 5 = 60

60 + 6 = 66

66 + 7 = 73

73 + 8 = 81

81 + 9 = 90

90 + 10 = 100

<em>100</em>

<u>Step 2:  Multiply</u>

100 * 2

<em>200</em>

Answer:  200

6 0
2 years ago
The sum of an unknown and eight is twenty. What is the unknown?<br>​
Zarrin [17]

indicates subtraction

20 - 8 = 12

4 0
2 years ago
Read 2 more answers
4/5 + 8/10 plz help with this
Lemur [1.5K]
 <span>4/5 + 8/10 =1.6

i hope this help</span>
5 0
3 years ago
Read 2 more answers
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