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3 years ago

Which of the following structures provides support and movement ?

Chemistry

2 answers:

quester [9]3 years ago

8 0

Answer:

The answer is C.

Explanation:

This is because you wouldn't be able to function without your lungs and spine. So therefore the answer would have to be "C".

Tomtit [17]3 years ago

5 0

Answer: D Bones and Muscles

Explanation:

The bones and muscles provide ,mobility to the body. The muscular and skeletal system both work together to support each other. Since both work together, this means they both play a large role in supporting the body and letting the body keep its posture.So yes D is correct because the bones support the muscle tissue and skin that will layer on top of it.

Hope this helps!

You might be interested in

Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).

zhenek [66]

Answer: a) 49.8 gram

b) 47.0 %

Explanation:

First we have to calculate the moles of glucose

$\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles$

The balanced chemical reaction will be,

$C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2$

From the balanced reaction, we conclude that

As,1 mole of glucose produce = 2 moles of ethanol

So, 0.54 moles of glucose will produce = $\frac{2}{1}\times 0.54=1.08$ mole of ethanol

Now we have to calculate the mass of ethanol produced

$\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}$

$\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g$

Now we have to calculate the percent yield of ethanol

$\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%$

Therefore, the percent yield is 47.0 %

7 0

3 years ago

If 980kJ of energy as heat are transferred to 6.2L of water at 291 K what will the final temperature be? The specific heat of wa

In-s [12.5K]

Answer:

Final temperature = T₂ = 328.815 K

Explanation:

Given data:

Given energy = 980 KJ = 980×1000= 980000 J

Volume = 6.2 L

Initial temperature =T₁= 291 K

Specific heat of water = 4.18 j /g .K

Final temperature = T₂ = ?

Formula:

Q = m. c . ΔT

ΔT = T₂ - T₁

we will first convert the litter into milliliter

6.2 × 1000 = 6200 mL

It is given in question that

1 mL = 1 g

6200 mL = 6200 g

Now we will put the values in formula,

Q = m. c . (T₂ - T₁)

980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)

980000 j = 25916 j/ k . (T₂ - 291 K)

980000 j / 25916 j/ k = T₂ - 291 K

37.8145 K + 291 K =T₂

T₂ = 328.815 K

4 0

4 years ago

What is the IUPAC name for the following compound?

djyliett [7]

Answer:

Option a. Benzenecarbonitrile

Explanation:

You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.

As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.

This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.

phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.

Hope this helps

5 0

3 years ago

A 312 g sample of a metal is heated to 277.845 °C and plunged into 200 g of water at a temperature of 11.945 °C. The final tempe

tigry1 [53]

Answer:

The specific heat capacity of the metal is 1.307 J/g °C

Explanation:

<u>Step 1:</u> Data given

mass of the metal = 312 grams

initial temperature of the metal ( before plunged in the water) = 277.845 °C

initial temperature water = 11.945 °C

Final temperature of water (and aslo the metal) = 99.062 °C

Specific heat capacity of wayer = 4.184 J/g °C

<u>Step 2:</u> Calculate the specifi heat capacity of the metal

Loss of Heat of the Metal = Gain of Heat by the Water

Qmetal = -Qwater

m(metal) * C(metal) * ΔT(metal) = - m(water) * C(water) * ΔT(water)

with mass of metal = 312 grams

with C(metal) = TO BE DETERMINED

with ΔT (metal) = 99.062 - 277.845 = -178.783 °C

with mass of water = 200 grams

with C(water) = 4.184 J/°C * g

with ΔT (water) = 99.062 - 11.945 = 87.117 °C

312 * C(metal) * -178.783 = - 200* 4.184 * 87.117

C(metal) = -72899.51 / 55780.296 = 1.307

The specific heat capacity of the metal is 1.307 J/g °C

6 0

3 years ago

Can someone good with chemistry help me?

Digiron [165]

As you go down group 7 the melting point of the elements will increase, this is because as you go down the group you are gaining an electron shell and the molecule will become bigger. This increase in size means that there will be an increase in the intermolecular forces as well.

So the order would be NF3, NBr3, NI3.

Hopefully this helps!

6 0

3 years ago