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stich3 [128]
3 years ago
12

Which term identifies a type of intermolecular force?

Chemistry
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer: (B) Hydrogen bonding

Radda [10]3 years ago
5 0

Answer: B. Hydrogen Bonding

Explanation: I got it right on castle learning lol

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Consider the decomposition of the compound C5H6O3 as follows: C5H6O3(g)  C2H6(g) + 3CO(g) A 5.63 g sample of pure C5H6O3(g) was
deff fn [24]

Answer:

K_{eq}=1.02x10^{-4}

Explanation:

Hello,

In this case, the first step is to compute the initial moles of C₅H₆O₃ as shown below:

5.63gC_5H_5O_3*\frac{1molC_5H_5O_3}{114gC_5H_5O_3}=0.0494molC_5H_5O_3

After that, by knowing that the final pressure is 1.63 atm, one computes the total moles at the equilibrium as follows:

n_{total}^{eq}=\frac{P_{total}^{eq}V}{RT}=\frac{1.63atm*2.50L}{0.082\frac{atm*L}{mol*K}*473.15K} =0.105mol

Then, by knowing the moles at the equilibrium considering the change "x", which yields to:

\ \ \ \ \  C_5H_6O_3(g) \leftrightarrow  C_2H_6(g) + 3CO(g)\\I\ \ \ \ \ 0.0494mol\ \ \ \ \ \ 0mol \ \ \ \ \ \ \ \ 0mol\\C\ \ \ \ \ \ -x\ \ \ \ \ \ \ \ \ \ \  \ \ x\ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x\\E\ \ 0.0494mol-x\ \ \ \ x\ \ \ \ \ \ \ \ \ \ \ \ \ 3x

The total moles at the equilibrium turn out:

n_{total}^{eq}=0.0494mol-x+x+3x

By solving for "x", we've got:

3x=0.105mol-0.0494mol\\x=\frac{0.0556mol}{3}\\x=0.0185mol

Finally, the equilibrium constant is:

K_{eq}=\frac{(x)(3x)^3}{0.0494-x}=\frac{(0.0185mol)(3*0.0185mol)^3}{0.0494mol-0.0185mol}=1.02x10^{-4}

Best regards.

4 0
4 years ago
How are the orbits of asteroids similar to, or different from planetary orbits?
Strike441 [17]
Aside from banks, what are 2 other places you might be able to borrow
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7 0
3 years ago
If apples are $.67/lb, what is the cost of 2.5 kg of apples?
Varvara68 [4.7K]

Answer:

The cost would be $1.68

Explanation:

I found the answer by multiplying

.67x or .67lb with 2.5, getting $1.68

8 0
3 years ago
Read 2 more answers
Question 3: Functional Groups<br> Identify the type of molecule from the name of the molecule.
cestrela7 [59]

Answer:

1. Organic Alcohol

2. Ester (specifically acetate ester)

3. Organic Alcohol

4. Carboxylic acid

5. Ketone

6. Ether

7. Amine

Explanation:

You can tell what type it is both from the nomenclature and looking at the functional group on the molecular structure. Hope this helps!

5 0
3 years ago
A 0.72-mol sample of PCl5 is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl3 (g) and 0
astra-53 [7]

Answer:

Equilibrium constant is 0.4

Explanation:

We propose the equilibrium:

                 PCl₅(g)    ⇄    PCl₃(g)   +    Cl₂(g)

Initially    0.72 mol

We have the 0.72 moles of the PCl₅.

React           x                      x                  x

X amount has reacted, so in the equilibrium we have:

               0.72 - x              0.4               0.4

If we initially have 0.72 moles and we have 0.4 moles at the equilibrium, it means that 0.3 moles has been reacted.

Let's make the expression for Kc:

Kc = [PCl₃] . [Cl₂] /  [PCl₅]

Kc =  0.4 . 0.4 / 0.4

Kc = 0.4

4 0
3 years ago
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