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labwork [276]
3 years ago
6

The graph shows the distance traveled by an Olympic-level sprinter over time during a race.

Mathematics
1 answer:
sweet [91]3 years ago
8 0

Answer:

l

Step-by-step explanation:

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If tanx=(b)/(a), find the value of \sqrt((a+b)/(a-b))+\sqrt((a-b)/(a+b)) in terms of x
Hitman42 [59]
Let's find at first \sqrt((a+b)/(a-b))

Let's find (a+b)(a-b)....

we should divide both side of fraction by b and we will get the following:
\frac{ \frac{a+b}{b} }{ \frac{a-b}{b} }  \\  \frac{ \frac{a}{b} + 1 }{ \frac{a}{b} - 1 }  \\ &#10;\frac{ tanx + 1 }{ tanx - 1 }

and (a-b)/(a+b) is same as (1/[(a+b)/(a-b)]) so we can use previous answer and finally we will have (a-b)/(a+b) = 1/[ (tanx + 1) / (tanx - 1)] = (tanx - 1)/(tanx + 1) and final answer will be this:

\sqrt{ \frac{tanx + 1}{tanx - 1} } +   \sqrt{ \frac{tanx - 1}{tanx + 1} }
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