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3 years ago

12

Ce Powered by MathXL - Inv. 2 - Thinking With Mathematical ... Copy 4

1 answer:

MAVERICK [17]3 years ago

7 0

Answer:

y=640-3x

Step-by-step explanation:

The total amount of ounces in the bucket is 640, and it decreases by 3 each minute. For example, if you plug in 3 for x into that equation (which would represent 3 minutes), you would lose 9 ounces of water, which makes sense in the terms of the equation.

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What is the volume of the pyramid

alexgriva [62]

Answer:

Option A - 32 cm³

Step-by-step explanation:

Volume of a pyramid is given by the formula :

V = $\frac{lwh}{3}$

Substituting values given gives us :

V = (4)(4)(6)/3

V = (16)(6)/3

V = 96/3

V = 32

Units will be cm³ as this is volume

Hope this helped and have a good day

5 0

1 year ago

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Each big square below represents one whole.<br><br> what percent is represented by the shaded area?

morpeh [17]

Answer:

100/27

Step-by-step explanation:

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3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

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Factor out the greatest common factor <br>-5x^2 - 5x^3 - 15x^4

vaieri [72.5K]

Our answer is $-5x^{2} (3x^{2} +x+1)$

Our greatest common factor, or GCF, is $-5x^{2}$ , so when we factor is out, our divide each term by $-5x^{2}$ , we get our answer. To check this, we can multiply the $-5x^{2}$ back across the parenthesis and see if we get the same result as our initial question.

Hope this helped! :))

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3 years ago

List all 6 whole numbers between -3.5 and 5.5

Alenkinab [10]

Answer012345

Step-by-step explanation:

5 0

3 years ago

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