How do you write X to the 4th power >>?
1 answer:
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Answer:
i. D:All real numbers
ii.R:
iii. Y-int:
Step-by-step explanation:
The given function is
The domain of this function are the values of x that makes the function defined.
The absolute value function is defined for all real values.
The domain is all real numbers.
ii. The range refers to the values of y for which x is defined.
The vertex of this function is
The function is reflected in the x-axis.
The vertex is therefore the maximum point on the graph of the function.
The range is therefore;
Or
![(-\infty,2]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C2%5D)
iii. To find the y-intercept, we substitute
into the funtion.
The y-intercept is
The graph is shown in the attachment.
i. D:All real numbers
ii.R:
iii. Y-int:
Step-by-step explanation:
The given function is
The domain of this function are the values of x that makes the function defined.
The absolute value function is defined for all real values.
The domain is all real numbers.
ii. The range refers to the values of y for which x is defined.
The vertex of this function is
The function is reflected in the x-axis.
The vertex is therefore the maximum point on the graph of the function.
The range is therefore;
Or
iii. To find the y-intercept, we substitute
The y-intercept is
The graph is shown in the attachment.
Answer:
see attached
Step-by-step explanation:
The equation is in the form ...
4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance
Comparing this to your equation, we see ...
p = 4, (h, k) = (3, 4)
p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...
vertex: (3, 4)
axis of symmetry: x = 3
focus: (3, 8) . . . . . 4 units up from vertex
directrix: y = 0 . . . horizontal line 4 units down from vertex
