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sashaice [31]
2 years ago
8

Victoria has $2.90 in quarters, dimes and nickels. The numbers of nickels is one more than six times the number of quarters, and

the number of dimes is 4 times the number of quarters. What is the total number of coins Victoria has.
Mathematics
1 answer:
maria [59]2 years ago
8 0

Answer:

Step-by-step explanation:

She has 290 cents.

Nickels: 6x+1

Quarters: x

Dimes: 4x

Now that we've converted it algebraically, we can add them

6x+1 + x + 4x = 11x+1 = 290

11x = 289

x = 289/11

let me know if incorrect, i will fix

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NeTakaya

A is the answer to this question because if you plug in 8.6-5 it is approximately 3

6 0
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6/2(1+2)=? Can someone help pretty please
barxatty [35]
First evaluate the value in the parenthesis: (1+2)=3
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4 0
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Expressions that are equivalent to <br> –<br> 8(q+6).
Alona [7]

Answer:

q = -6

Step-by-step explanation:

8(q + 6)

= (8×q) (8×6)

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8 0
3 years ago
How does the experimental probability of choosing a yellow tile compare with the theoretical probability of choosing a yellow ti
Evgen [1.6K]

Answer:

The experimental probability is the same as the theoretical probability.

Step-by-step explanation:

The given data is:

color            observed frequency               relative frequency

Red                            15                                          3/10

Blue                           12                                          6/25

Green                         8                                           4/25

Yellow                        10                                          1/5

Purple                         5                                           1/10

The experiment was repeated 50 numbers of times.

Solution:

Theoretical probability is basically what is expected to happen without experimenting and experimental probability is what actually happens as a   results of an experiment.

Theoretical probability =  favorable outcomes / all possible outcomes

Experimental probability = no. of times outcome occurs / no. of times

                                                                                      experiment is performed The experimental probability  and theoretical probability are same i.e. 1/5

This can be seen from the table:

Experimental probability = 1/5

As the experiment is performed 50 times and the outcome (yellow tile) occurs 10 times so using the formula of experimental probability:

10/50 = 1/5

Now as given, there are 5 number of tiles (red,blue,green,yellow,purple) so number of possible outcomes is 5. Yellow tile among these 5 tiles is 1. So the favorable outcomes is 1. So looking at the given formula of theoretical probability:

1/5

So

experimental probability = 1/5

theoretical probability = 1/5

Hence the experimental probability is the same as the theoretical probability.

4 0
2 years ago
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
2 years ago
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