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iVinArrow [24]
3 years ago
10

PLEASE HELP what is 30th term of -12, -3, 6, 15

Mathematics
1 answer:
hoa [83]3 years ago
5 0

Answer:

249

Step-by-step explanation:

We can see that the difference of every term in the given sequence is 9, because -12 + 9 = -3, -3 + 9 = 6 and 6 + 9 = 15. We may therefore assume that the sequence is <em>arithmetic </em>(a fancy word of saying that a sequence is increasing with a constant value every term).

Since the difference of every term is 9, we know that the explicit form of the sequence (where the value of every term is expressed in terms of the term number) is in the form 9n+c, where n is the term number and c is a constant we are going to figure out right now.

We know that the first term of the sequence is -12, so we see that9(1) + c = -12 and hence c=-21. Therefore, the 30th term of the sequence is 9(30) - 21 = 249.

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Answer:

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Step-by-step explanation:

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HACTEHA [7]

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13.7

Step-by-step explanation:

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Svetlanka [38]

Answer:

x = 7

Step-by-step explanation:

Notice that in the triangle, the angle is either known or in terms of x. This means we can make an equation: 82 + (9x - 6) + (6x - 1) = 180. Now, add up tthe terms to get 15x + 75 = 180, or 15x = 105 or x = 7.

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4 years ago
Find P on AB that is 2/3 of the distance from A(-3,-5) to B(9,4).
Ludmilka [50]

A line segment can be divided into ratios.

<em>The coordinate of P on line segment AB is (5,1)</em>

Given

A = (-3,-5)

B = (9,4)

The position of P from A to B is:

P_A = \frac 23

So, from P to B would be:

P_B =1 -  \frac 23

P_B = \frac 13

So, the ratio is:

m : n = \frac 23 : \frac 13

Simplify

m : n = 2 :1

<u>The coordinate of point P is:</u>

P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

So, we have:

P = (\frac{2 \times 9 + 1 \times -3}{2 + 1},\frac{2 \times 4 + 1 \times -5}{2 + 1})

P = (\frac{15}{3},\frac{3}{3})

P = (5,1)

<em>Hence, the coordinate of P is (5,1)</em>

Read more about line ratios at:

brainly.com/question/8847082

8 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
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