First find the length of the hypotenuse using pythagorean theorem
<span>c^2 = 5^2 + 7^2
c^2 = 25 + 49
c^2 = 64
c=8 (take the square root in both sides)
Since sin = opposite/hypotenuse,
sin = 5/8 = 0.625</span>
Answer:
Answer to fourth part is :
Angle ABC= Angle DBC
So for fifth part reason answer is ASA congruency.
Step-by-step explanation:
Here we are given that CB bisects angle ABD and angle ACD.
So we have ,
Angle ABC= Angle DBC
Answer to fourth part is :
Angle ABC= Angle DBC
Now here we have two angles and one side equal in two triangles.
So we can say that ASA congruency fits in the best here.
So for fifth part reason answer is ASA congruency.
The answer is C.
You need you use Pythagoras theorem 2 times to have 2 equations with the same sides i.e. for example a2 + b2 = 81 and a2 - b2 = 9.
You can do it as you have different triangles but with the same sides.
X% of 150 = 108
x/100 * 150 = 108
1.5x = 108
x =108 / 1.5
x = 72
Therefore 72% of 150 is 108
Hope this helps.
3:5=x:50
Therefore 5 ×x = 50
x = 10
Therefore 3 × 10 = 30
therefore 30 blue pens
proof = 30 blue + 50 red= 3+ 5
therefore 80 = 8x
