What are facts about complementary angles?

Solve for x, where x is a real number.

Alex787 [66]

Hello!

First of all, let's undo the square roots by squaring both sides.

6x+2=9x-8

We subtract 9x from both sides.

-3x+2=-8

We subtract 2 from both sides.

-3x= -10

We divide both sides by -3.

x=10/3

I hope this helps!

7 0

3 years ago

Read 2 more answers

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

Marina CMI [18]

<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

$f(-x)=-f(x)$

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

$f(-x)=f(x)$

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

$\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x$

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function is symmetric about the origin.</em>

7 0

3 years ago

You sell pies at a farmers' market for $7.50 each. A group of 5 kids wants to pitch in equal1y to share one of your pies. How mu

Korolek [52]

Its 5 divided my 7.50 since each decided to pitch in to help by the pie

3 0

3 years ago

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The kittens, Annie and Josie, are pushing a ball, Annie with a force magnitude of 80 N in a direction of 133 degrees, and Josie

kvv77 [185]

Answer: Then the magnitude of the force is 37.86N, and the direction is 54.35°

Step-by-step explanation:

We can write the forces as vectors.

We know that Annie pushes with a magnitude of 80N in a direction of 133° (Remember that the angles are always measured from the x-axis)

The components of this force, (Ax, Ay), are then:

Ax = 80N*cos(133°)

Ay = 80N*sin(133°)

And we know that Josie pushes with a magnitude of 95N in direction of 290°

The components of this force, (Jx, Jy), are:

Jx = 95N*cos(290°)

Jy = 95N*sin(290°)

When we add these forces, the total force acting on the ball is:

F = (80N*cos(133°) , 80N*sin(133°)) + (95N*cos(290°), 95N*sin(290°))

F = (80N*cos(133°) + 95N*cos(290°), 80N*sin(133°) + 95N*sin(290°))

Now, the third kitten wants to do a force K, in a direction θ, such that the net force acting on the ball is zero.

Then we must have that, each component of the force of the third cat (K*cos(θ) on the x-axis and k*sin(θ) on the y-axis), is such that:

K*cos(θ) + 80N*cos(133°) + 95N*cos(290°) = 0

k*sin(θ) + 80N*sin(133°) + 95N*sin(290°) = 0

Now we need to solve that system for k and θ

if we simplify the equations we get:

k*cos(θ) - 22.07N = 0

k*sin(θ) -30.76N = 0

Now we can rewrite them as:

k*cos(θ) = 22.07N

k*sin(θ) = 30.76N

Now we can take the quotiet between both equations to get:

(k*sin(θ))/(k*cos(θ)) = 30.76N/22.07N

Tan(θ) = 1.394

θ = Atan(1.394) = 54.35°

Now that we know the angle, we can find the value of the magnitude k, by using one of the two equations of the system:

k*cos(54.35°) = 22.07N

k = 22.07N/cos(54.35°) = 37.86N

Then the magnitude of this force is 37.86N, and the direction is 54.35°

7 0

3 years ago

In ΔEFG, f = 86 inches, e = 64 inches and ∠E=32°. Find all possible values of ∠F, to the nearest degree.

Neporo4naja [7]

Answer:

Answer: 45 ∘ and 135 ∘

Step-by-step explanation:

Delta Math

7 0

3 years ago