Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
24?
Step-by-step explanation:
I'm not very good at math and I'm sorry if I'm wrong.
Answer:
The answer to your question is the second choice
Step-by-step explanation:
4x/ (x - 7) - (x +7) / x
- Find the greatest common factor from x and (x - 7)
GCF = x(x - 7)
- Substract the terms
[4x(x) - (x + 7)(x - 7)] / x(x - 7)
- Simplify
[ 4x² - x² + 49] / x(x - 7)
[ 3x² + 49] / x(x - 7)
- Result
3x² + 49 / x(x - 7)
Answer:
203
Step-by-step explanation:
17*7=119
12*7=84
84+119=203