All categories

3 years ago

MARKING BRAINLIEST IF CORRECT + 50 POINTS!!!!

Mathematics

2 answers:

melamori03 [73]3 years ago

6 0

Answer:

Part A : 1/62 Part b : 1/60

Step-by-step explanation:

Well lets start with part A

(62)x=1

anything in parenthesis means multiply

62x= 1

divide everything by 62 to get x by itself

x= 1/62

Part A : 1/62

Part B : 60x = 1

x = 1/60

because same reasoning

allochka39001 [22]3 years ago

4 0

Answer:

The first one is 0, the second one is ARN (All real numbers)

Step-by-step explanation:

1. Anything raised to the "zeroth" power is always 1

2. Because 7 is being raised to the zeroth power, the number inside the parentheses becomes 1. Now x can equal anything, 1 times itself will always equal 1, no matter how many times you multiply them.

Step-by-step explanation:

You might be interested in

a line passes through the point (6, -9) and has a slope of 3/2. write an equation in point-slope form for this line

Stella [2.4K]

Y=3/2x is the answer

3 0

3 years ago

Read 2 more answers

Solve: q + 24 = 24 A. q = 8 B. q = 2 C. q = 3 D. q = 0

vekshin1

Answer:

Hi! The answer to your question is D. q = 0

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☁Brainliest is greatly appreciated!☁

Hope this helps!!

- Brooklynn Deka

3 0

3 years ago

What is the answer of (1/100)+ (1.6)(2.1)

adell [148]

Answer:

3.37

Step-by-step explanation:

I am not very sure but this would be the answer.

7 0

4 years ago

Read 2 more answers

Two equiangular decagons are congruent. Sometimes/Always/Never

OLga [1]

Answer:

Two equiangular decagons are sometimes congruent.

4 0

3 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

7 0

4 years ago