Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation =
= 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.
Answer:
f =
/x
Step-by-step explanation:
Let's solve for f.
fx=−0.52+2
Step 1: Divide both sides by x.
fx
x
=
1.75
x
f=
1.75
x
(20+5)+(10+6)
you are supposed to use place value to break it down
x = 40/2 = 20 i think thsts the answer if I was wrong you have to right to slap my face