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maw [93]
3 years ago
10

Can someone help me with this please

Mathematics
2 answers:
tatiyna3 years ago
7 0
The answer to this is 4 !!
otez555 [7]3 years ago
3 0

Answer:

i have done this so its 2

Step-by-step explanation:

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Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
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Suppose the lengths of two strings are 10 centimeters and 17 centimeters. Describe how the lengths of these two strings compare
Nina [5.8K]
• There is a 7 centimeter difference
• They both have 10 centimeters
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Dominic makes bread to sell at his local farmers' market. It costs $1.58 for Dominic to make a loaf of bread. How much money wil
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Answer:

$1.58X12=$18.96

Step-by-step explanation:

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A golfers score after playing on friday was +2
jek_recluse [69]

The end of his round on Saturday was a -5, and the end of his round on Sunday was a 0.

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Liling is a salesperson at a computer store she recurves a base salary of $2,300 per month and she receives a commission of 3% o
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Answer:

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Step-by-step explanation:

<u>Total earning:</u>

  • Salary + commission + extended warrant fee
  • 2300 + 0.03*44000 + 41*8 =
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