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maw [93]
3 years ago
10

Can someone help me with this please

Mathematics
2 answers:
tatiyna3 years ago
7 0
The answer to this is 4 !!
otez555 [7]3 years ago
3 0

Answer:

i have done this so its 2

Step-by-step explanation:

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The water at the end of a pier was 28 meters deep at midnight. As the tide came in, the water depth increased at a rate of 0.012
Nastasia [14]

Answer:

  0.012t + 28 = 30

Step-by-step explanation:

The depth starts at 28 meters. The amount of increase in t minutes will be 0.012t, so the total depth after t minutes is ...

  0.012t +28

We want to find when that is equal to 30, so the appropriate equation is ...

  0.012t +28 = 30

4 0
3 years ago
In one area, the lowest angle of elevation of the sun in winter is 24degrees Find the distance x that a plant needing full sun c
sweet [91]

Answer:

round answer is : 10 ft

Step-by-step explanation:

The explanation is in the picture!

5 0
3 years ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

6 0
4 years ago
Which best explains why the equation 3x+8=3x-5 has no solutions?
tekilochka [14]
3x + 8 = 3x - 5
3x - 3x + 8 = -5
8 = -5 (incorrect)
this means there is no solution, because whatever number u sub in for x, it will not come out true
6 0
3 years ago
Read 2 more answers
Solve for r: i=prt<br> please help
babymother [125]

Answer:

hmm

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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