5.75 if you don’t count the lunch break because I don’t think a lunch break can be twelve hours because it would’nt even be a shift
: Let y = f(x) = x^1/3
Then dy = 1/3*x^(−2/3) dx
Since f(64) = 4.
We take x = 64 and dx = ∆x = 1
This gives dy = 1/3*(64)^(−2/3)* (1) = 1/48
∴65^(1/3) = f(64 + 1) ≈ f(64) + dy = 4 + 1/48 ≈ 4.021 <span>
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Answer:
6+1x=y
Step-by-step explanation:
-just add 6 because you will only pay it once to enter the fair
-place x for the number of rides the person gets on and 1 next to it to multiply
- place Y at the end because we don't know how much the person spent
That "9 minutes" doesn't affect the outcome!
How many pieces of candy are in the bag at the beginning? How many of those are "fruit tart chews?" Write a fraction involving these 2 counts. Remember that Britany immediately eats what she draws from the bag, so the 2nd time around, there are only 19 pieces, not 20. What is the prob. that she will pick a jelly treat on her second draw?
Because these experiments are independent, you can find the joint probability by multiplying the 2 probabilities together. Please show your work.
C = 10d+ 45 ? Hope this helps? Let me know if it’s right or not.
