If the total value of the coins is $15. The number of each type of coin is: 31 quarters, 72 dimes.
<h3>Number of each type of coin</h3>
Let D = number of dimes
Let Q = the number of quarters
Equations
d + q = 103
0.10d + 0.25q = 15
d = 103 -q
0.10(103 -q) + 0.25q = 15
10.3 - 0.10q + 0.25q = 15
0.15q = 4.7
q=4.7/0.15
q=31 quarters
Substitute q into second equation
D+31=103
D=72 dimes
Therefore the number of each type of coin is: 31 quarters, 72 dimes.
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Answer:
wow thats mean
Step-by-step explanation:
Answer:
It seems each number is 3 less than the previous number.
We must sum these 10 numbers
40, 37, 34, 31, 28, 25, 22, 19, 16, 13
The sum would equal the average of the middle 2 numbers times 10.
(28 + 25) / 2 = 53 / 2 = 26.5
We multiply by 10 because there are 10 numbers and this equals
265
Step-by-step explanation:
6(2k-3) is the answer to this problem.
make a distributive
take the 6 out of the equation and u have remaining 2k-3. 6(2k-3)
Answer:
t(32) = 94
Step-by-step explanation:
a. I think s is the independent variable
b I think t or t(s) is the dependent variable since the total amount of money depends on how many treats are sold.
t(32) = 30 + 2(32)
t(32) = 30 + 64
t(32) = 94
I'm a little unsure on the dependent and independent variable but I know the function is correct.
Hope this helps :)
