Answer:
hi
Step-by-step explanation:
the function is c(x) = 31 + 0.18*x
where $31 is a fixed cost, and $0.18 is the cost per mile drive (where the number of miles driven)
So the fixed cost, $31, is the cost per day of rent (this price does not depend on the number x), and the linear cost, $0.18, is the cost per mile driven (because this number is multiplied by x in the function), then the right answer is B: "$31 is the cost per day to rent the car and $0.18 is the cost per mile."
300=(1/6*7/8)x
300=7/48x
300*48=7x
14400=7x
2057=x
So the answer is B
Hope this helps :)
B (2x+5y=-10) is the answer.
Answer: x= -6; y= -1
Step-by-step explanation:
-4x + y = 23
4x - 9y = - 15
-4x + y = 23
y = 23 + 4x [Add 4x to both side]
4x - 9(23 + 4x) = - 15
4x - 207 - 36x = - 15
-32x - 207 = -15
-32x = 192 [Add 207 to both side]
x = -6 [Divide -32 from both side]
-4x + y = 23
-4(-6) + y = 23 [Plug in -6 for x]
24 + y = 23 [Subtract 24 from both side]
y = -1
Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).