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Rashid [163]
3 years ago
13

HELP ME PLEASE IM BEGGING YOU

Mathematics
1 answer:
WITCHER [35]3 years ago
5 0

Answer:

Parallel

Step-by-step explanation:

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Can someone answer this please so I can go to the back page
igomit [66]
Blake has 25 CD's.

25 times 3 = 75
75 + 7 = 82

Joel has 82 CD's.

If Joel has twice as many as Mariella, then divide 82 by 2 and you get 41.

Mariella has 41 CD's.
7 0
4 years ago
SoIve the system of equations by elimination. (Addition)<br> 1)-2x + 4y = -22<br> 2x + 8y = –26
Rufina [12.5K]

Answee:

We have these two equations:

-2x +4y =-22

2x + 8y -26

We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:

2x + 8y =-26  ---- -2x - 8y =26

Now we have this:

-2x +4y = -22

-2x -8y = 26

Now e substract both equations:

-2x - (-2x) +4y -(-8y) = -22-26

12y = -48

Y = -48/12 = -4

And we replace to get x

-2x + 4y = -22

-2x +4*(-4)=-22

-2x - 16 = -22

x= -6/-2 =3

6 0
3 years ago
Read 2 more answers
Which of the tables represents a function?
Vanyuwa [196]
The answer is table D as it is the only one without a repeated input ❤️ hope that helps
7 0
3 years ago
Read 2 more answers
Please help! College Algebra!
german
The volume would be (x+1)x(x+4)x(3x)= (x^2+x+4x+4)x(3x)= (x^2+5x+4)x(3x)= (3x^3)+(15x^2)+(12x)
Hence, the answer is the 4th option.
Hope this helped you, and if it did, please mark it as the brainiest answer. I would really appreciate it!
4 0
3 years ago
Kendra needs 1 dollar to buy a ball she has 73 cents what coins does she need to add her 73 cents
Alexeev081 [22]

Answer:

Kendra needs 3 coins (1 coin of 25 cent & 2 coins of 1 cent)  to add 27 cents in 73 cents to make 1 dollar

Step-by-step explanation:

Given :

Kendra has 73 cents

She need 1 dollar to by a ball

∴ She requires additional money = 1\ dollar - 73 \ cents = 27 \ cents

Standard Coins available are 50 cents , 25 cents, 10 cents, 5 cents and 1 cent.

To make 27 cents =  25+1+1 = 1 coin of 25 cent & 2 coins of 1 cent

5 0
3 years ago
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