A right-angled triangle has sides of lengths (x+5)cm, (x-3)cm and 9cm. Calculate the value of x. Give your answer to 3 significa nt figures. (Quadratic Formula)
1 answer:
Answer:
x = (3.95 and -5.95)
Step-by-step explanation:
Given:
Hypotenuse = 9 cm
Perpendicular = (x+5) cm
Base = (x-3) cm
Find:
Value of x
Computation:
Using Pythagoras theorem
Hypotenuse² = Perpendicular² + Base²
9² = (x+5)² + (x-3)²
81 = x² + 25 + 10x + x² + 9 - 6x
2x² + 4x - 47 = 0
Quadratic Formula
x = [-b±√b²-4ac] / 2a
x = [-4±√16+376] / 2(2)
x = (3.95 and -5.95)
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