Answer:
<em><u>ALKYLATING AGENTS</u></em>
Explanation:
Examples of alkylating agents include chlorambucil, cyclophosphamide, thiotepa, and busulfan.
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Answer:
1/64
Explanation:
Parent 1: AaBbCc
Parent 2 : AaBbCc
When the cross is checked for individual gene:
Aa X Aa =
A a
A AA Aa
a Aa aa
Probability of producing an AA organism is 1/4
Similarly, probability of producing a BB from Bb X Bb would be 1/4
Probability of producing a CC from Cc X Cc would be 1/4
Hence, probability of producing an AABBCC would be:
1/4 * 1/4 * 1/4 = 1/64
The correct answer is C= I think so
