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8_murik_8 [283]
3 years ago
9

Perform the indicated operation. 6-7i/6 + i

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer: (28/37) - (48/37)*i

Step-by-step explanation:

We want to solve the quotient:

\frac{6 - 7*i}{6 + i}

To solve it, we need to multiply the whole quotient by the complex conjugate of the denominator.

Remember that for a complex number:

a + b*i

the complex conjugate is:

a - b*i

Then if the denominatoris:

6 + i

the complex conjugate is:

6 - i

Then to solve the quotient we have:

\frac{6 - 7*i}{6 + i} *\frac{6 - i}{6 - i} =  \frac{(6  -7*i)*(6 - i)}{(6 + i)*(6 - i)} = \frac{6*6 -7*6*i - 6*i + (-7*i)*(-i)}{6*6 +6*i - 6*i -i^2}

This is equal to:

\frac{6*6 -7*6*i - 6*i + (-7*i)*(-i)}{6*6 +6*i - 6*i -i^2} = \frac{36 - 42*i - 6*I - 7}{36 + 1}  = \frac{29 - 48*i}{37}

Then the initial quotient is equal to:

(28/37) - (48/37)*i

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There are 10 circles and 2 triangles. What is the simplest ratio of triangles to total shapes?
barxatty [35]

Answer:

1:6

Step-by-step explanation:

Given that there are 10 circles and 2 triangles, the total number of shapes is equal to 10+2.

10+2=12

Because there are 2 triangles, the ratio of triangles to total shapes is equal to 2:12.

However, this ratio can be simplified because both sides are multiples of 2. Divide both sides of the ratio by 2 to simplify the ratio.

2:12

1:6

Therefore, the simplest ratio of triangles to total shapes is 1:6.

I hope this helps!

5 0
3 years ago
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Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

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4 0
2 years ago
A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po
Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call h the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is h - 49.

The wire length d is 14 ft longer than height h, hence

d= h+14.

Thus we get a right triangle with hypotenuse d= y+14, perpendicular  h, and base h-49; therefore, the Pythagorean theorem gives

(h-49)^2+h^2 = (h+14)^2

which upon expanding we get:

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further simplification gives

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which is a quadratic equation with solutions

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Since the first solution h =21ft will give the triangle base length of 21ft-49ft = -28ft which is negative; therefore, we disregard it and pick the solution h = 105ft.

Hence, the height of the pole is 105ft.

3 0
3 years ago
Three more than six times a number equals -5. what is the number?
DerKrebs [107]

Answer:

-4/3

Step-by-step explanation:

first we can name this number x

so then our equation would be

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then subtract 3 from both sides

6x=-8

divide both sides 6

x=-8/6

simplify

x=-4/3

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4 years ago
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