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Irina18 [472]
3 years ago
10

Cassidy wrote the linear equation y=5x+4. Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes th

rough (8,–2). If her new equation is in the form y=5x+b, what is the value of b?
Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0
All you need to do is plug in the point.
y=5x+b
(-2) = 5(8) + b
-2 = 40 + b
b = -42
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Need An Answer ASAP ... THANK YOU !!!
lozanna [386]

Answer:

∠EFG = 48°

Step-by-step explanation:

As FH bisects ∠EFG , ∠EFH = ∠HFG .

We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°

Also, ∠HFG  + ∠EFH = ∠EFG

=> 2(-5x + 89)° = (61 - x)°

=> -10x + 178 = 61 - x

=> 10x - x = 178 - 61

=> 9x = 117

=> x = 117 / 9 = 13

Putting the value of 'x' in ∠EFG gives :-

(61 - x)° = (61 - 13)° = 48°

8 0
4 years ago
The area of a compact disc is 452 4/7 square centimeters. What is the diameter of a compact disc ? Use 22/7 as an approximation
motikmotik

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6 0
3 years ago
Which equation describes a line parallel<br> to y= 4x+ 5 through point (-2, 1)?
Tema [17]

Hi there!

For a line to be PARALLEL, it must contain the same slope.

The given line has a slope of 4, so we can use the point-slope formula to solve:

\large\boxed{y - y_1 = m(x - x_1)}

y1 = y-coordinate of given point

x1 = x-coordinate of given point

m = slope

Plug in the values:

y - 1 = 4(x - (-2))\\\\y - 1 = 4(x + 2)

Simplify:

y - 1 = 4x + 8\\\\\boxed{y = 4x + 9}

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2 years ago
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