The domain of the ellipse is [-4. 6] and the range of the ellipse is [-4. 0]
<h3>How to determine the domain and the range of the ellipse?</h3>
The equation of the ellipse is given as:
4x^2 + 25y^2 – 8x + 100y + 4 = 0
Next, we plot the graph of the ellipse
See attachment for the graph of the ellipse
<u>The domain</u>
From the attached graph the minimum and the maximum values of x are:
Minimum = -4
Maximum = 6
So, the domain of the ellipse is [-4. 6]
<u>The range</u>
From the attached graph the minimum and the maximum values of y are:
Minimum = -4
Maximum = 0
So, the range of the ellipse is [-4. 0]
Hence the domain of the ellipse is [-4. 6] and the range of the ellipse is [-4. 0]
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Answer:
13 degrees
Step-by-step explanation:
mPQR=25 degrees , mRQT=11 degrees.
mPQT=PQR-RQT
MPQT=25-11=13 degrees
Answer:
x = 5
Step-by-step explanation:
Since we know that the diagonals bisect each other and divide into equal parts so ➡
x - 2 = 2x -7
2x - x = 7 - 2
x = 5
Answer:
9
Step-by-step explanation:
so sorry if im too late...
Answer:
blah 23 =67=43
Step-by-step explanation: