We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.
<h3>What is the extraneous solution?</h3>
In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.
As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.
Let's suppose the equation is:
Squaring both the sides:
x + 4 = (x - 2)²
x + 4 = x² - 4x + 4
x² -5x = 0
x = 0 or x = 5
Checking for the solution by plugging in the equation;
3 = 3
2 ≠ -2
The solution x = 0 shows extraneous solution.
Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.
Learn more about the extraneous solution here:
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Answer:
1) The determinant = 65
2) The determinant = 152
Step-by-step explanation:
Let us show how to find the determinant of a matrix
You can find the determinant of this Matrix ![\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&m&n\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%26c%5C%5Cd%26e%26f%5C%5Cg%26m%26n%5Cend%7Barray%7D%5Cright%5D)
by using this rule
Determinant = a(en - fm) - b(dn - fg) + c(dm - eg)
Let us use this rule with the given matrices
1)
![\left[\begin{array}{ccc}1&-1&3\\2&5&0\\-3&1&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%263%5C%5C2%265%260%5C%5C-3%261%262%5Cend%7Barray%7D%5Cright%5D)
The determinand = 1[(5)(2) - (0)(1)] - (-1)[(2)(2) - (0)(-3)] + 3[(2)(1) - 5(-3)]
= 1[10 - 0] - (-1)[4 - 0] + 3[2 - (-15)]
= 1[10] + 1[4] + 3[2+15]
= 10 + 4 + 3[17]
= 10 + 4 + 51
= 65
The determinant = 65
Let us do the second one
2)
![\left[\begin{array}{ccc}-1&-8&2\\9&1&0\\4&1&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-8%262%5C%5C9%261%260%5C%5C4%261%262%5Cend%7Barray%7D%5Cright%5D)
The determinand = -1[(1)(2) - (0)(1)] - (-8)[(9)(2) - (0)(4)] + 2[(9)(1) - 1(4)]
= -1[2 - 0] - (-8)[18 - 0] + 2[9 - 4]
= -1[2] + 8[18] + 2[5]
= -2 + 144 + 10
= 152
The determinant = 152
Check the picture below
get the volume of each, sum them up, that's the volume of the figure
Answer:
The zeros of the given function 
is 
are -8 and -9.
Step-by-step explanation:
Given : Function
We have to find the zeros of the functions.
Consider the given Function
Since, we have to find the zeros of the given functions.
Put f(x) = 0
Thus, 
We can solve the given equation using middle term splitting method.
17x can be written as 8x + 9x
can be written as 
Taking x common from first two term and 9 common from last two terms, we have,
Simplify, we have,
or 
x = -8 and x = -9
Apply zero product rule,
Thus, The zero of the given function is are -8 and -9.
I believe the answer would be h. For every value (x,y) of the function f, h has the inverse (y,x).
