Question

1.Prove that the roots of x^2 + (1 - k).x+k-3 = 0 are real for all real values of k​

Answer 1

Step-by-step explanation:

${x}^{2} + (1 - k)x + k - 3 = 0$

${x}^{2} + x - 3 = 0$

Use the discramnt formula.

${ {b}^{2} - 4ac }$