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Aloiza [94]
3 years ago
13

The length of Rectangle A is 20 inches and the width is 4 inches. The length of Rectangle B is

Mathematics
2 answers:
evablogger [386]3 years ago
7 0

Answer:

8"

Step-by-step explanation:

Lᵃ/Wᵃ = Lᵇ/Wᵇ

20"/4" = 40"/Wᵇ

Wᵇ = (4"×40")/20"

Wᵇ = 160" ÷ 20"

Wᵇ = 8"

Width of rectangle B = 8 inches

______________

#IndonesianPride

- kexcvi -

astraxan [27]3 years ago
5 0

Answer:

8 inches

Step-by-step explanation:

Let w be the width of rectangle B.

Since, both rectangles are similar.

Therefore, corresponding lengths and widths of rectangles A and B will be in proportion.

\therefore \frac{20}{40}  =  \frac{4}{w}  \\  \\  \frac{1}{2}  =  \frac{4}{w}  \\  \\ w = 2 \times 4 \\  \\ w = 8 \: inches

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          Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.

[23] ABD = 42°, DBC = 35°

(4x - 2) + (3x + 2) = 77°

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[24] ABD = 62°, DBC = 78°

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Which expression is equivalent to 440d2 - 176d?
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