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Natasha_Volkova [10]
3 years ago
7

Need help ASAP! due soon!!!

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

Option B

Step-by-step explanation:

First make x = 4 and y = 3 in the equation y = -1/2x + 5

it should look like 3 = -1/2(4) + 5 now we can solve

   -1/2 * 4 = -2         →      3 = -2 +5

       -2 + 5 = 3         →          3 = 3

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Help ASAP please ! I’ll give points
ale4655 [162]

The answers D

Step-by-step explanation:

the answer is D because to fine slope, you have to do rise over run

hope this help : )

5 0
3 years ago
Sin(A+B) sin(A-B) /sin^A Cos^B=1-cot^A Tan^B​
telo118 [61]

In order to prove

\dfrac{\sin(x+y)\sin(x-y)}{\sin^2(x)\cos^2(x)}=1-\cot^2(x)\tan^2(y)

Let's write both sides in terms of \sin(x),\ \sin^2(x),\ \cos(x),\ \cos^2(x) only.

Let's start with the left hand side: we can use the formula for sum and subtraction of the sine to write

\sin(x+y)=\cos(y)\sin(x)+\cos(x)\sin(y)

and

\sin(x-y)=\cos(y)\sin(x)-\cos(x)\sin(y)

So, their multiplication is

\sin(x+y)\sin(x-y)=(\cos(y)\sin(x))^2-(\cos(x)\sin(y))^2\\=\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)

So, the left hand side simplifies to

\dfrac{\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}

Now, on with the right hand side. We have

1-\cot^2(x)\tan^2(y)=1-\dfrac{\cos^2(x)}{\sin^2(x)}\cdot\dfrac{\sin^2(y)}{\cos^2(y)} = 1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}

Now simply make this expression one fraction:

1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}=\dfrac{\sin^2(x)\cos^2(y)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}

And as you can see, the two sides are equal.

6 0
4 years ago
Turn upside down but somebody HELP!
bogdanovich [222]
Part of the answer is covered up.

Get  a better picture please

8 0
3 years ago
4. Your school is having a fundraiser. You are selling candy bars that have been donated by the Hershey
fiasKO [112]

Answer:

120x + $20 = $200

x = $1,5

Step-by-step explanation:

We need to find out the price of each candy bar we sold. Let's define x, our variable, as this price that we need to find out.

We know that we met the goal of raising $200 by selling candy bars and with the $20 donation. We need to have this in mind when we write the equation.

Therefore, if we multiply the 120 candy bars we sold by the unit price and we add the $20, it has to be equal to $200.

In math language, that is

120x + $20 = $200

Let's solve it to find out the x. First we subtract $20 from both sides:

120x + $20 - $20 = $200 - $20

120x = $180

Now we divide by 120:

120x/120 = $180/120

x = $1,5

We sold the candy bars for $1,5 each.

We can also interpret that we met the goal and exceed it. The calculation is the same but we need to change the equal sign with a greater sign, because the amount we raise was greater than $200. That is

120x + $20 > $200

With the same calculations, we will get

x > $1,5

That means that the candy bars were sold for more than $1,5 each.

7 0
3 years ago
Solve the equation. 7b -0.5 = 8b​
Lera25 [3.4K]

Answer:

b = -0.5

Step-by-step explanation:

7b -0.5 = 8b

7b - 0.5 + 0.5 = 8b +0.5

7b -8b = 8b + 0.5 -8b

-x = 0.5

x = -0.5

3 0
3 years ago
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