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attashe74 [19]
3 years ago
9

A.5x=3x B.5=3 how can we get equation B from equation A?

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

9514 1404 393

Answer:

  divide by x

Step-by-step explanation:

To answer your question, you can get from A to B by dividing by x:

  5x=3x\\\\\dfrac{5x}{x}=\dfrac{3x}{x}\qquad\text{only if $x\ne0$}\\\\5=3

However, this is only a valid operation if x ≠ 0. In this equation, x = 0, so that division is not valid.

__

A better approach to the solution is to put the equation in standard form:

  f(x) = 0

You can get there by subtracting 3x from both sides.

  5x -3x = 3x -3x

  2x = 0

Now, you can legitimately divide by 2 to find ...

  x = 0 . . . . . . . . the reason why dividing by x is not allowed

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Answer:

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Step-by-step explanation:

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Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

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Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

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By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

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