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kykrilka [37]
2 years ago
8

True or false - A risk ratio and an odds ratio are different names for the same concept

Mathematics
1 answer:
aalyn [17]2 years ago
6 0
True would be right
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A cube has a side length of 5 cm. If this cube is enlarged by a scale factor of 2, What is the enlarged cubes side length. Pleas
zhenek [66]

Answer:

Length of the enlarged cube is 10 cm.

Step-by-step explanation:

We are given that,

Length of the cube = 5 cm.

The cube is enlarged by a scale factor of 2.

Since, enlargement increases the size of the figure.

So, the length of the cube will increase by a factor of 2.

That is,

Length of the enlarged cube = 5 × 2 = 10 cm

Hence, the length of the enlarged cube is 10 cm.

7 0
4 years ago
I WILL GIVE BRAIN THING
Romashka-Z-Leto [24]

Answer:

1) Combine the x tiles to get: \mathbf{4x}

2) Combine integer tiles to get: 3

3) The equivalent function is: \mathbf{4x+3}

4) If we Substitute any value of x both expressions will be equivalent

Step-by-step explanation:

We are given expression: x+x+x+x++4-1\\

We need to complete following statements.

1) Combine the x tiles to get:

x+x+x+x\\=4x

Combine the x tiles to get: \mathbf{4x}

2) Combine integer tiles to get:

+4-1\\=3

Combine integer tiles to get: 3

3) The equivalent function is:

x+x+x+x++4-1\\\\4x+3

The equivalent function is: \mathbf{4x+3}

4) If we Substitute any value of x both expressions will be equivalent

Verifying:

x+x+x+x+4-1=4x+3\\Let\: x = 1\\1+1+1+1+4-1=4(1)+3\\4+4-1=4+3\\7=7

So, Both expressions are equivalent.

8 0
3 years ago
Read 2 more answers
36.18 litres = _____ litres ______millilitres
german

36 litres 180 millilitres

Hope this helps!

5 0
2 years ago
Nicola is multiplying 1/6 by 4/2
guajiro [1.7K]
5/12 or approximately 0.417
6 0
3 years ago
A psychologist thinks that listening to Mozart helps people think. She gives subjects a set of puzzles and measure how many they
BigorU [14]

Answer: 0.8

Step-by-step explanation:

Let's assume that 5 puzzles were solved in 5mins. That is, 1min for each puzzle to be solved.

From our assumption, our sample size will be 5.

The probability that a subject will solve more than 1 puzzle will be number of occurrence from 2 to 5 which is 4.

This gives: 4/5 = 0.8 to one decimal place.

4 0
4 years ago
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