The interquartile range is 4
a is the answer to the problum !
Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center ( in radians)
In this case m < theta = 360 - 235 = 125 degrees or 2.182 radians
So, the area of shaded area = 1/2 * 20^2 * 2.182 = 436.4 in^2
Answer:
11.46 I believe
Step-by-step explanation:
Answer:
Option A. 
Step-by-step explanation:
we know that
In the right triangle MNL
Applying the Pythagoras Theorem

substitute the values

