Question

Find the vertex for the equation: y = 3x^2 + 18x + 30 (-3, 3) (-3, -51) (3, 111)

Answer 1

I think (-3, 3 ) !!!!!!!!!!!

Answer 2

Y = 3x^2 + 18x + 30
a = 3, b = 18, c = 30

h = -b/2a = -18 / 6 = -3
k = (4ac – b^2) / 4a = (360 - 324)/12 = 36/12 = 3

vertex (h, k) = (-3,3)


answer
(-3, 3)