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tia_tia [17]
3 years ago
13

Solve the system of equations by any method. 5x+9y =16 x+2y =4

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

The system of equations has one solution at (-4, 4).

Step-by-step explanation:

We are given the system of equations:

\displaystyle\left \{ {{5x+9y=16} \atop {x+2y=4}} \right.

We can use elimination to solve this system. We need to multiply the second equation by -5 so we can cancel out our x-terms.

-5\times(x+2y=4) \rightarrow -5x - 10y = -20

Therefore, our system now becomes:

\displaystyle\left \{ {{5x+9y=16} \atop {-5x-10y=-20}} \right.

Now, we can add these two equations together and solve for y.

\displaystyle(5x + 9y) + (-5x - 10y) = 0 - y\\\\16 + (-20) = -4\\\\-y = -4\\\\\frac{-y}{-1}=\frac{-4}{-1}\\\\y = 4

Now, we can substitute our value for y into one of the equations and solve for x.

x+2(4)=4\\\\x + 8 = 4\\\\x = -4

Therefore, our final solution is (-4, 4).

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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

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