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NikAS [45]
3 years ago
6

Whats the equation for this​

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

x^2 + y^2 + 4x + 4y  = -119/16

Step-by-step explanation:

The axes x and y are calibrated in 0.25

If the circle is carefully considered, the radius r of the circle is:

r = -1.25 - (-2)

r = 0.75 units

The equation of a circle is given by:

(x - a)^2 + (y - b)^2 = r^2

The center of the circle (a, b) = (-2, -2)

Substituting  (a, b) = (-2, -2) and r = 0.75 into the given equation:

(x - (-2))^2 + (y - (-2))^2 = (3/4)^2\\\\(x + 2)^2 + (y + 2)^2 = (3/4)^2\\\\x^2 + 4x + 4 + y^2 + 4y + 4 = 9/16\\\\x^2 + y^2 + 4x + 4y + 8 = 9/16\\\\16x^2 + 16y^2 + 64x + 64y + 128 = 9\\\\16x^2 + 16y^2 + 64x + 64y  = -119\\\\x^2 + y^2 + 4x + 4y  = -119/16\\

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Answer:

B

Step-by-step explanation

the answer comes to x\leq 20 and 15 is the only answer below 20

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2 years ago
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Simplify This Radical Expression
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Answer:

The answer is: -0.5198

Step-by-step explanation:

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Hope this helps! Have an Awesome day!! :-)

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2 years ago
Help with trigonometry​
Oksanka [162]

Answer:

○B. \frac{\sqrt{6}}{2}

Step-by-step explanation:

Trigonometric Identities

\frac{y}{r} = sin\:θ

\frac{x}{r} = cos\:θ

\frac{y}{x} = tan\:θ

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<u>Radius Formula</u>

{y}^{2} + {x}^{2} = {r}^{2}

{[-\sqrt{15}]}^{2} + {[-\sqrt{10}]}^{2} = {r}^{2} → 15 + 10 = {r}^{2} → 25 = {r}^{2}\\ \\ 5 = r

* Since we are talking about radii, we only want the NON-NEGATIVE root.

In this case, we will not be using the radius in our ratio, according to the trigonometric identity above because we are using the <em>tangent</em><em> </em>ratio:

\frac{\sqrt{6}}{2} = \frac{-\sqrt{15}}{-\sqrt{10}} = \sqrt{1\frac{1}{2}}

I am joyous to assist you anytime.

4 0
3 years ago
Shade the model to 0.5 x 0.3
stellarik [79]
What model? also it would be 1/2 and 1/3
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3 years ago
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Answer:

(-1 1/2, 6)

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Hence,the coordinates, that is, AP: x = (-3 + 0)/2 = -3/2 = -1 1/2

also, BP: y = (6 + 6)/2 = 6

Therefore, the coordinates of point P = ( -1 1/2, 6)  

7 0
2 years ago
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