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Olin [163]
4 years ago
10

X = ?? a) 1 b) 3 c) 7

Mathematics
1 answer:
Lina20 [59]4 years ago
3 0

Answer:

X=3

Step-by-step explanation:

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<h3>How to calculate reference angles</h3>

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Answer:

t=\frac{190-180}{\frac{23}{\sqrt{100}}}=4.348    

df=n-1=100-1=99  

p_v =2*P(t_{(99)}>4.348)=0.000033  

Since the p value obtained for this case is a very low value we have enough evidence to reject the null hypothesis that the true mean is equal to 180 at many of the possible significance levels commonly used.  So then makes sense the claim that the true mean for the weigth is different from 180

Step-by-step explanation:

Information provided

\bar X=190 represent the mean weight

s=23 represent the sample standard deviation for the weight

n=100 sample size  

\mu_o =180 represent the value to compare

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to determine if the true mean weight is different from 180 pounds, the system of hypothesis would be:  

Null hypothesis:\mu = 180  

Alternative hypothesis:\mu \neq 180  

We don't know the population deviation for the variable of interest so then the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the data given we got:

t=\frac{190-180}{\frac{23}{\sqrt{100}}}=4.348    

Now we can find the p value but first we need to find the degrees of freedom given by:

df=n-1=100-1=99  

Since we are conducting a two tailed test the p value can be calculated on this way:

p_v =2*P(t_{(99)}>4.348)=0.000033  

Since the p value obtained for this case is a very low value we have enough evidence to reject the null hypothesis that the true mean is equal to 180 at many of the possible significance levels commonly used.  So then makes sense the claim that the true mean for the weigth is different from 180

4 0
3 years ago
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