Answer:
The flagpole's shadow is 16.875 feet longer than the man's shadow
Step-by-step explanation:
The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;
Height of the shadow=actual height of the flagpole×factor
where;
length of the flagpole's shadow=22.5 feet
actual height of the flagpole=32 feet
factor=f
replacing;
22.5=32×f
32 f=22.5
f=22.5/32
f=0.703125
Using this factor in the expression below;
Length of man's shadow=actual height of man×factor
where;
length of man's shadow=m
actual height of man=8 feet
factor=0.703125
replacing;
length of man's shadow=8×0.703125=5.625 feet
Determine how much longer the flagpole's shadow is as follows;
flagpoles shadow-man's shadow=22.5-5.625=16.875 feet
The flagpole's shadow is 16.875 feet longer than the man's shadow
Answer:
a = 36
Step-by-step explanation:
We use pythagoras theorem here.
h = 60
p = 48
b = a
h² = p² + b²
60² = 48² + b²
3600 = 2304 + b²
b² = 3600 - 2304
b² = 1296
b = 36
Answer:
y = 1/2x+8.5
Step-by-step explanation:
From (-11,3) to (-7,5) you get an average of 4 units to the right and 2 units up, divide that and you get 2 units right and 1 unit up in which the middle is (-9, 4). Add that until you get to (1, 9), go back one unit to get (0, 8.5), the slope is 1/2x because it is going 1 unit up and 2 units right.
The figure is rotated 90 degrees counterclockwise around the origin and then translated to the right 6 units.
