Answer:
The turns of a graph is represented by the number of maximum or minimum that the function has.
If we differenciate f(x) we get:
f'(x)=4x^3+6x
f'(x)=2x(2x^2 + 3)
Therefore f'(x) =0, when x=0. Given that negative roots are not defined.
Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.
Attached you find the graph of the function which confirms the number of turns.
If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!
23 3/4 rounds because you can take 95 divided by 4 to get 23 3/4 rounds
Let
x--------------> a number
we know that
<span>three sets of a sum of a number and four----------> 3(x+4)
t</span><span>he sum of 7 times the same number and 13--------> 7x+13
therefore
</span>(Three sets of a sum of a number and four) are added (to the sum of 7 times the same number and 13) ----------> [3(x+4)] + [7x+3]
[3(x+4)] + [7x+3]------> [3x+12] + [7x+3]=10x+15
the answer is 10x+15
The correct answer is the last option:) hope u get an 100%!
Answer:
1st option
i know for sure and....
Last one totally wrong
Step-by-step explanation:
