5.65 in decimal and 113/20
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2
Answer:
18
Step-by-step explanation:
The multiples of 6 are : 6, 12, 18, 24, 30, ......
The multiples of 2 are : 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, ......
The multiples of 9 are : 9, 18, 27, 36, ......
The common multiple is 18
The least common multiple is 18
Since the scale factor is smaller than one (the original), the resulting image is smaller than the original.
Hope this helped, and feel free to ask more questions if needed(:
So the first four terms of the sequence are
2, 6, 10, 14