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PSYCHO15rus [73]
2 years ago
6

3(x+2)=62 find the correct solution

Mathematics
1 answer:
valkas [14]2 years ago
8 0

Answer:

\frac{56}{3} or 18\frac{2}{3}

Step-by-step explanation:

First:

Divide both sides by 3 (you need to get x by itself)

\frac{3(x+2)}{3} = \frac{62}{3}

Second:

Subtract both sides by 2

x+2 = \frac{63}3 -2

And Finally just simplify

x = \frac{56}{3}

or you can make it into a mixed fraction which is 18\frac{2}{3}

(just divide on the calculator)

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Jane is building a bookcase with 4 shelves. Each shelf is 24 inches long. How much wood does Jane need to make the 4 shelves?
Ksivusya [100]

Answer: 96 inches of wood

Step-by-step explanation:

24 × 4 = 96

So he would need 96 inches of wood!

Hope this helps!!! Good luck!!! ;)

7 0
3 years ago
HELLLLLLLLLLLPPPPPPPPPP
natka813 [3]
Answer
y = 4x + 4

slope: (36-16)/(8-3)=4
intercept: 16=3(4)+b -> b=4
7 0
3 years ago
4. 46 is what percent of 69?
sergij07 [2.7K]

Answer:

66%(technically 0.66 repeating)

Step-by-step explanation:

We need to figure out what percentage of 69 equates to 46. In other words, we need to figure out what percentage <u>times</u> 69 equals 46:

percentage*69 = 46

Now that we formed this equation, we can solve for the percentage as if it was x.

First lets simplfy:

percentage*69 = 46 -- > 69percentage = 46

Now we can solve for x just by getting x alone, which means we must remove the coefficent. We can do this by dividing both sides of the equation by 69:

percentage = \frac{46}{69}

=

percentage=0.66

Putting this into the form of percentage, we must multiply by 100. Since, the percentage form of a decimal is 100 times bigger(moved up 2 decimal places):

percentage = 0.66*100

=

percentage = 66%

Hope this helps! :3

4 0
2 years ago
How many solutions does the following equation have?<br> -5(2+1) = –22 + 10
Igoryamba

Answer:

0 real # solution

Step-by-step explanation:

b^2-4ac<1 is equal to 0 real number solution and

-5(2+1)=-22+10

-5(2+1)=-12

which is less than 1

7 0
3 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
4 years ago
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