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3 years ago

Select the correct answer.

Mathematics

2 answers:

devlian [24]3 years ago

6 0

What the first guy said lol Ehhehe

timurjin [86]3 years ago

3 0

Answer:

1. A cross section parallel to the base of a right rectangular prism is a square. This is false as the cross section will be a rectangle if the base is rectangular and square if the base is a square.

Step-by-step explanation:

I hope this helps

Brainly is ur best friend

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For what value(s) of t, with 0 ≤ t ≤ 4, is the slope of the curve undefined for the graph defined by x = 2t - 2 sin(t), y = 2 -

Flauer [41]

Answer:

Step-by-step explanation:

4 0

3 years ago

Claire’s mother is 4 years more than twice Claire’s age. The sum of their ages is 58 years.

vichka [17]

Claire is 18 years old and her mother is 40 years old.

Step-by-step explanation:

Let,

Claire's age = x

Her mother's age = y

According to statement;

x+y=58 Eqn 1

y=2x+4 Eqn 2

$Putting\ Eqn\ 2\ in\ Eqn\ 1\\x+(2x+4)=58\\x+2x+4=58\\3x+4=58\\3x=58-4\\3x=54\\Dividing\ both\ sides\ by\ 3\\\frac{3x}{3}=\frac{54}{3}\\x=18$

Putting value of x in Eqn 2

$y=2(18)+4\\y=36+4\\y=40$

Claire is 18 years old and her mother is 40 years old.

Keywords: Linear equations, Substitution method

Learn more about substitution method at:

#LearnwithBrainly

7 0

3 years ago

How do you solve this???????? Please help. the answer is not 72.17. explain your answer. thank you so much!!

Delicious77 [7]

What do you need help with? it helps us to know the question!

6 0

3 years ago

Please I need help!!!!!!

8090 [49]

Answer:

What? I'm in middle school ;-;

Step-by-step explanation:

8 0

3 years ago

For the function given below, find a formula for the Riemann sum obtained by dividing the interval [0,5] into n equal subinterva

sergij07 [2.7K]

Given

we are given a function

$f(x)=x^2+5$

over the interval [0,5].

Required

we need to find formula for Riemann sum and calculate area under the curve over [0,5].

Explanation

If we divide interval [a,b] into n equal intervals, then each subinterval has width

$\Delta x=\frac{b-a}{n}$

and the endpoints are given by

$a+k.\Delta x,\text{ for }0\leq k\leq n$

For k=0 and k=n, we get

$\begin{gathered} x_0=a+0(\frac{b-a}{n})=a \\ x_n=a+n(\frac{b-a}{n})=b \end{gathered}$

Each rectangle has width and height as

$\Delta x\text{ and }f(x_k)\text{ respectively.}$

we sum the areas of all rectangles then take the limit n tends to infinity to get area under the curve:

$Area=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)$

Here

$f(x)=x^2+5\text{ over the interval \lbrack0,5\rbrack}$ $\Delta x=\frac{5-0}{n}=\frac{5}{n}$ $x_k=0+k.\Delta x=\frac{5k}{n}$ $f(x_k)=f(\frac{5k}{n})=(\frac{5k}{n})^2+5=\frac{25k^2}{n^2}+5$

Now Area=

$\begin{gathered} \lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{5}{n}(\frac{25k^2}{n^2}+5) \\ =\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{125k^2}{n^3}+\frac{25}{n} \\ =\lim_{n\to\infty}(\frac{125}{n^3}\sum_{k\mathop{=}1}^nk^2+\frac{25}{n}\sum_{k\mathop{=}1}^n1) \\ =\lim_{n\to\infty}(\frac{125}{n^3}.\frac{1}{6}n(n+1)(2n+1)+\frac{25}{n}n) \\ =\lim_{n\to\infty}(\frac{125(n+1)(2n+1)}{6n^2}+25) \\ =\lim_{n\to\infty}(\frac{125}{6}(1+\frac{1}{n})(2+\frac{1}{n})+25) \\ =\frac{125}{6}\times2+25=66.6 \end{gathered}$

So the required area is 66.6 sq units.

3 0

1 year ago