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a_sh-v [17]
2 years ago
5

7. An example for using estimation would be:

Mathematics
2 answers:
Aliun [14]2 years ago
4 0
Guessing the number of pennies in a jar
stiks02 [169]2 years ago
4 0
The answer should be c I hope it helps My friend have a nice day
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The table shows the total number y (in billions) of U.S. movie admissions each year for x years. Use a graphing calculator to fi
wariber [46]

Answer:

By rounding up of the constant and coefficient terms, we have;

The line of best, fit is y = 1.23 + 3.46 × 10⁻²·x

Step-by-step explanation:

The table for the data on the number of movie admissions each year is presented as follows;

Year, x                                             {}                      Admission, y

0                                                      {}                         1.24

2                                                       {}                        1.26

4                                                      {}                         1.39

6                                                      {}                         1.47

8                                                      {}                         1.49

10                                                      {}                        1.57

Using a graphing calculator, we have that the line of best fit is given by the following equation;

y = 1.23047619048 + 3.45714285714 × 10⁻²·x

Which is approximately, y = 1.23 + 3.46 × 10⁻²·x

3 0
3 years ago
What is the value of X?
NISA [10]

Answer:

I think the answer for this question is 2.24cm

4 0
3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
Scorpion4ik [409]

Answer:

x=4/3y

The grapgh is below

Hope This Helps!!!

8 0
2 years ago
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Common Denominators<br> 15. Explain how you can find a common denominator for and
VLD [36.1K]
You can find a common denominator using the two denominators multiples.
6 0
3 years ago
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