Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.
So we can use formula of perimeter of rectangel to find it's possible dimensions.
We knwo that perimeter of the rectangle is given by 2(L+W)
where L is lenght and W is width.
Given perimeter is 20 so we get:
2(L+W)=20
L+W=10
L=10-W
So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.
Let W=4
Then L=10-W=10-4=6
Hence we just have to draw a rectangle having length 6 and width 4.
So the final answer will be picture in the attached graph.
Answer: = 1 8/6
Step-by-step explanation: hope this helps, have an awesome day!!
Answer: 416
Step-by-step explanation:
The area of a trapezoid is h(a+b)/2. So 16(14+38)/2 = 416
Step-by-step explanation:
exponents are subracted when divided
so next step is
24x/5y and this is the answer
Answer:
It is not a right triangle
This is a scalene triangle
Step-by-step explanation:
A right triangle is a triangle in which one of the angles is a 90∘ angle. If the lengths satisfy the Pythagorean Theorem (a2+b2=c2) then it is a right triangle.
This cannot be obtuse b/c it does not add up to 180.
A triangle is scalene if all of its three sides are different (in which case, the three angles are also different).
