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3 years ago

14

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1 answer:

Flauer [41]3 years ago

7 0

Answer:

k

Step-by-step explanation:

k

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Answer the following 2 question

Zanzabum

Answer:

Step-by-step explanation:

ii) Perimeter = 8 + 7 + 17 + 16 + (17-8) + (16-7)

=8+ 7 + 17 +16 + 9 + 9

= 66 m

Area = area of upper rectangle + area of lower rectangle

= 8*7 + 16*9

= 56 + 144

= 200 m²

8 0

2 years ago

Let u=<-5,1>, v=<7,-4> find 9u-6v

katrin2010 [14]

9u -6v = 9<-5, 1> -6<7, -4>
.. = <9*-5 -6*7, 9*1 -6*-4>
.. = <-87, 33>

8 0

2 years ago

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The histogram shows the number of morning customers who visited North Cafe and South Cafe over a one-month period. Which predict

vlabodo [156]

The answer to the question is

B. The north restaurant can expect to have 20 fewer morning visitors than the south restaurant.

Hope this helps!

8 0

2 years ago

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Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

Find 118% of 19 could really use some help late bloomer

Zanzabum

Hello,

<span>to find the percent of a number what we have to do is to multiply the number by de percent that we want to know and divide by 100, so:
</span>
$19* \frac{118}{100} =22.42$

Answer: 118% of 19 is 22.42

7 0

3 years ago

Read 2 more answers