(C) "having a deep fondness for border collies and therefore overestimating them"
While acknowledging that "dogs may be noble, charming, loyal, and dependable," the author of Passage 1 speculates that they might not have "earned those extra intellect points." In contrast, the author's admiration for dogs may lead one to believe that the depiction of "pure intelligence shining in the face of a border collie" in lines 63–67 is exaggerated.
The answer is not (A). Passage 1's author would probably assume that Passage 2's author has a strong emotional bond with dogs. (B) is the wrong answer. The subjective assessment of canine intellect is shown in lines 63–67. They don't imply that the author of Passage 2 has in-depth understanding of the relevant studies.
The answer is not (D). Despite the fact that the author of Passage 2 appears to prefer personal experience over the findings of scientific investigations, lines 63–67 do not demonstrate any scorn for "traditional" research. The answer is not (E).
It would be harsh to assert that the author of Passage 2 has a limited understanding "of what constitutes intelligence" despite the fact that the two authors may hold different opinions on the degree to which dogs are able to reason.
Here's another question with an answer similar to this about dogs:
brainly.com/question/18951741
#SPJ4
9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
Attached is the sketch
X-axis intersections:
(-3,0)
(0,0)
(1,0)
Points of inflection:
(-1,319,-2.881) Concave upward
(0.569,1.041) Concave downward
Step-by-step explanation:
Desmos (I'm not allowed to post the link, pls search it up) is a great help for these type of problems!
