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2 years ago

3x=21 im being times

Mathematics

1 answer:

katovenus [111]2 years ago

4 0

Answer: X=7

Step-by-step explanation: 7 times 3 is 21.

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What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%2A%2081" id="TexFormula1" title="\frac{2}{3} * 81" alt="\frac

Vaselesa [24]

Hello!

<u><em>Answer: ⇒⇒⇒⇒⇒⇒⇒ =54</em></u>

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Step-by-step explanation:

First you had to convert element to fraction.

$\frac{2}{3}*\frac{81}{1}$

Then you had to cross out by the common factor of 3.

$\frac{2}{1}=\frac{27}{1}$

Multiply by the fraction.

$\frac{2*27}{1*1}$

Multiply by the number.

$2*27=54$

$=\frac{54}{1*1}$

Again multiply by the number.

$1*1=1$

$=\frac{54}{1}$

Apply rule.

$\frac{54}{1}=54$

54 is the right answer.

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Hope this helps!

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-Charlie

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4 0

3 years ago

Write the terms a 1a1, a 2a2, a 3a3, and a 4a4 of the following sequence. If the sequence appears to converge, make a conjec

Arturiano [62]

Answer:

Step-by-step explanation:

WE are given that $a_n = \frac{(-1)^{n+1}}{5n-4}$ . Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then

$a_1 = \frac{(-1)^2}{5(1)-4} = \frac{1}{1}= 1$

$a_2 = \frac{(-1)^3}{5(2)-4} = \frac{-1}{6}$

$a_3 = \frac{(-1)^4}{5(3)-4} = \frac{1}{11}= 1$

$a_4 = \frac{(-1)^5}{5(4)-4} = \frac{-1}{16}= 1$

Note that as n increase, $a_n$ gets closer to 0. So, the limit of this sequence is 0.

6 0

3 years ago

PLEASE HELP I'LL MARK BRAINLIEST!!!!!

WARRIOR [948]

The answer is B And C

7 0

2 years ago

Read 2 more answers

How do you add fractions with a whole number? Please explain the rules of it too! To be marked as brainliest

eimsori [14]

Hello this is how you do it!<3

9/4 = 21/4 therefore, 9/4 = 21/4

24/10 try to reduce the numerator and denominator by a common denominator 24/10 divided 2/2 = 12/5

16/2 divided 2/2 = 8/1 = 8

I hoped that help!<3

6 0

2 years ago

Plz I need helpppp!!!!

allochka39001 [22]

Answer:

Just Guess

Step-by-step explanation:

You Have More Than One Try... Thats What I Do With Multiple Awnsers

3 0

3 years ago