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3 years ago

11

In a sample of 45 mice, a biologist found that 18 were able to run a maze in 30 seconds or less. Find the limits for the 95% con

fidence interval to estimate the population proportion of mice who can run a maze in 30 seconds or less

1 answer:

Hunter-Best [27]3 years ago

4 0

Answer:

fugltuha jxghd rkdrjvjxcrtz tcdytsfuigjr xdyeg

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$\bold{\text{Answer}:\quad x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)=1.09}$

<u>Step-by-step explanation:</u>

$7.8e^{\frac{x}{3}\cdot ln(5)}=14\\\\\\e^{\frac{x}{3}\cdot ln(5)}=\dfrac{14}{7.8}\\\\\\ln\bigg(e^{\frac{x}{3}\cdot ln(5)}\bigg)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\frac{x}{3}}\cdot ln(5)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\large\boxed{x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)}\\$

x ≈ 1.09

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